Question 807691
You need two points on the line in order to graph it.
First get the equation in slope-intercept form: y = mx + b 
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3x + 2y = 8
2y = -3x + 8
y = (-3/2)x + 4
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Plug-in two different x values in the equation to get their y values, like so: 
Point p1, use x=0:
y = (-3/2)(0) + 4
y = 4
p1 = (0, 4)
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Point p2, use x=2:
y = (-3/2)(2) + 4
y = -3 + 4
y = 1
p2 = (2, 1)
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To check the work, calculate the slope using the two points, like so:
slope: m = (y2 - y1)/(x2 - x1)
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m = (1 - 4) / (2 - 0)
m = -3/2
The work is correct. This slope matches the slope-intercept form above: y = (-3/2)x + 4
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Now draw a line between points p1 and p2 to graph the equation. 
The line extends infinitely beyond both points.
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