Question 807586
Find all possible numbers where twice the reciprocal of the square of a number, less three times the reciprocal of a number is -1 
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Let the number be "x"::
Equation:
2(1/x)^2 - 3(1/x) = -1
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Rearrange::
2(1/x)^2 -3(1/x) + 1 = 0
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Note: That is a quadratic with variable 1/x.
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Factor::
(2(1/x) -1)((1/x)-1) = 0
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(1/x) = 1/2 or (1/x) = 1
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Answer:: x = 2 or x = 1
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