Question 807510
What you have is 2 linear equations.
That means that you've got a {{{ y }}}
and an {{{ x }}} and not a {{{ y }}} and
an {{{ x^2 }}} or {{{ x^3 }}}
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A linear equation just means that the plot
is a straight line. Two equations are called
a system, and teh solution will be a
point ( x,y ) that satisfies both equations
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{{{ 2x - y = 2 }}}
{{{ 3x - 2y = 11 }}}
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Multiply both sides of (1) by {{{ 2 }}} and
subtract (1) from (2)
{{{ 3x - 2y = 11 }}}
{{{ -4x + 2y = -4 }}}
{{{ -x = 7 }}}
{{{ x = -7 }}}
Now plug this result back into either 
equation to find {{{ y }}}
{{{ 2x - y = 2 }}}
{{{ 2*(-7) - y = 2 }}}
{{{ -14 - y = 2 }}}
{{{ -y = 14 + 2 }}}
{{{ -y = 16 }}}
{{{ y = -16 }}}
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So, the solution is ( -7 ,-16 )
Here a plot of both lines showing the 
intersection at ( -7, -16 )
{{{ graph( 400, 400, -10, 10, -30, 6, 2x - 2, (3/2)*x - 11/2 ) }}}