<PRE><B>Question 807490</B>
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Since the small circle is internally tangent to the larger one, the distance from B to the the larger circle has to be equal to the distance between the two circle centers.  Hence the radius of B is 5 and the radius of A is 10.


Calculate:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \pi(10^2)\ -\ \pi(5^2)]


Leave your answer in terms of *[tex \Large \pi] for an exact answer.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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