Question 807419
A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present ages.

son ----------x years
father------------2x years

12 years ago
son = x-12 years
father= 2x-12

2x-12=2(x-12)

2x-12=4x-48

4x-2x=48-12

2x=36
x=18


son = 18 years
father = 2x= 36 years