Question 807441
3x^2-2x-5=0

Find the roots of the equation by quadratic formula					
		,b=			
a=	3		-2	c	-5
		-			
b^2-4ac=	16		600		
b^2-4ac=	616				
{{{sqrt(	616	)}}}=	24.82		
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}					
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}		+			
x1=(	4		24.82	)/	6
x1=	4.8				
x2=(	4		) /	6	
x2=	-3.470