Question 807381
{{{abs(a+5)/2>6}}}

{{{abs(a+5)>2*6}}}
{{{abs(a+5)>12}}}


Look at the conditions a+5 being negative and non-negative.


{{{a+5>=0}}}?
{{{abs(a+5)=a+5}}}.
{{{a+5>12}}}
{{{a>12-5}}}
{{{a>7}}}


{{{a+5<0}}}?
{{{abs(a+5)=-(a+5)=-a-5}}}.
{{{-a-5>12}}}
{{{a+5<-12}}} notice the change direction of inequality.
{{{a<-12-5}}}
{{{a<-17}}}


The solution is the union of those two results.  Saying what is a, {{{a<-17}}} OR {{{a>7}}}, since these are two non-overlapping regions of the real numbers.