Question 68373
3Y-2X=5
3Y=2X+5
Y=2X/3+5/3 THUS THIS LINE HAS A SLOPE OF (2/3) & A LINE PERPENDICULAR TO THIS LINE THEN HAS A SLOPE OF THE NEGATIVE RECIPRICAL OF THIS SLOPE. THUS THE NEW SLOPE IS(-3/2). NOW SUBSTITUTE THE POINTS THROUGH WHICH THIS NEW LINE PASES  (4,2) FOR THE X & Y VALUES IN THE EQUATION ---- 
Y=mX+b WHERE (m=SLOPE) & SOLVE FOR THE Y INTERCEPT (b) THUS:
2=-3/2*4+b
2=-12/2+b
2=-6+b
2+6=b
8=b WHICH IS THE Y INTERCEPT OF THE NEW LINE. THUS THE EQUATION OF THIS LINE IS
Y=-3/2X+8