Question 8849
Take it like any fractions you would multiply.

{{{(x^2y/5x)* (5y/x^2y^2)}}} 

Multiply the numerator by the numerator and the denominator by the denominator.  First, you multiply the coefficients.  In this case, an understood 1 in the first fraction times the 5 in the second fraction produces 5.  Then you multiply the variables.  {{{x^2y*y=x^2y^2}}}  So our numerator is {{{5x^2y^2}}}

Now we multiply the denominators.  Coefficients first.  5 in the first denominator, and 1 in the second.  Our coefficient part is 5.  Then, the variables.  {{{x*x^2y^2=x^3y^2}}}  Our denominator is {{{5x^3y^2}}}

Finally, we have our fraction.  {{{5x^2y^2/5x^3y^2}}}

Now we can cancel.  The five and the five cancel each each other out, as do the {{{y^2}}}'s, and we can cross out the {{{x^2}}} from the bottom and simplify the top to only {{{x}}}.  We are left with {{{x/1}}}, or {{{x}}}.  I hope this helped.