Question 807045
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There are four suits.  Four of each would be 16, so it is possible to draw 16 cards and only have four of each suit.  One more and you would be assured of having five of one suit.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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