<PRE><B>Question 807021</B>
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Distance equals rate times time so distance divided by time is rate.  Total speed downstream is *[tex \Large r_s\ +\ r_c] and total speed upstream is *[tex \Large r_s\ -\ r_c] where *[tex \Large r_s] is speed in still water and *[tex \Large r_c] is the speed of the current.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r_s\ -\ r_c\ =\ \frac{420}{12}\ =\ 35]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r_s\ +\ r_c\ =\ \frac{330}{6}\ =\ 55]


Both values in feet per minute.  Solve the 2X2 system for *[tex \Large r_s] and *[tex \Large r_c]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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