Question 806760
log(base4)(x-9)-log(base4)(x+3)=2
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{{{log(4,(x-9))-log(4,(x+3))=2}}}
{{{log(4,((x-9)/(x+3))=2)}}}
convert to exponential form
4^2=(x-9)/(x+3)=16
16(x+3)=x-9
16x+48=x-9
15x=-57
x=-57/15
no solution: (x+3)>0