Question 806665
1-cos^2x/tan^2x=sqrt3/2
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for interval[0,2π]
{{{(1-cos^2(x))/tan^2(x)=sqrt(3)/2}}}
{{{(sin^2(x))/(sin^2(x)/cos^2(x))=sqrt(3)/2}}}
{{{cos^2(x)=sqrt(3)/2}}}
take sqrt of both sides
cos(x)≈±0.9306
x≈0.3747, 2.7668, 3.5163, 5.9084