Question 806892
You can think of this as the slower group standing
still and the other group approaching at the
sum of their speeds
Let {{{ s }}} = the speed of the slower group in mi/hr
{{{ 2.5s }}} = the speed of the faster group in mi/hr
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{{{ 100 = ( s + 2.5s )*200 }}}
{{{ .5 = s + 2.5s }}}
{{{ 3.5s = .5 }}}
{{{ s = .1429 }}} mi/hr
{{{ 2.5s = .3573 }}} hrs
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Their speeds are .1429 mi/hr and .3573 mi/hr
check:
Slower group:
{{{ d[1] = .1429*200 }}}
{{{ d[1] = 28.58 }}}
Faster group:
{{{ d[2] = .3573*200 }}}
{{{ d[2] = 71.46 }}}
{{{ d[1] + d[2] = 28.58 + 71.46 }}}
{{{ d[1] + d[2] = 100.04 }}}
close enough