<PRE><B>Question 806817</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  f(x)\ =\ \frac{2}{x}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  f(x\,+\,a)\ =\ \frac{2}{x\,+\,a}]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{f(x\,+\,a)\ -\ f(x)}{a}\ =\ \frac{\frac{2}{x\,+\,a}\ -\ \frac{2}{x}}{a}]


Simplify and you are done.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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