Question 68299
{{{ 2/(a-b) + 1/(a+b)}}}

Here's how to solve for this 
Step 1. Multiply each term with the least common denominator. In this expression the LCD (Least Common Denominator) will be (a-b)(a+b)
{{{ ((a-b)(a+b))2/(a-b) + ((a-b)(a+b))1/(a+b)}}}
In the first term a-b will be cancelled and in the second term a+b.
Our new expression now is 
{{{(2(a+b))+ (1(a-b))}}}
Combine like terms and simplify
{{{(2a + 2b) + (a - b)}}}
2a + a + 2b - b
3a + b