Question 806630
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Yes, it would be a function if you consider that a negative function value is nonsensical, hence it makes sense to restrict the range.  The type of function is predicated on which of the several possible choices you make for the independent variable.


If you want to solve for *[tex \Large t] it is an exponential function.   If you want to solve for *[tex \Large r], except for very odd circumstances where *[tex \LARGE nt\ \not\in\ \mathbb{N}], this would be a polynomial function.  If you know the period interest rate, that is *[tex \LARGE \frac{r}{n}], then calculating *[tex \Large n] is an exponential function also.


If you are solving for either A or P for a fixed period, rate, and number of compounding periods so that the exponential part becomes a constant, then you have a linear function.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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