Question 68308
For all real numbers a, a is not equal to 0, and for all positive integers m 
and n:
If m > n then {{{ a^m/a^n}}} = {{{ a^(m-n)}}} If m < n then {{{ a^m/a^n}}} = {{{ 1/(a^(n-m))}}} If m = n then {{{ a^m/a^n}}} = {{{a^0}}} = 1


{{{(-96)W^4L^8M^2/-24M^2W^2L^6 }}}
Write the constant as {{{-96/-24}}} then look at the variables.
The variable W, 4 > 2 so we are going to rewrite it as  {{{W^(4-2)}}}
The Variable L, 8 > 6 so we have {{{L^(8-6)}}}
The Variable M, 2 = 2 so we have {{{M^0}}} which is equal to 1


Restate the expression

{{{ (-96)W^(4-2)L^(8-6)(1)/-24}}} simplify 


Therefore our answer is
{{{ 4W^2L^2}}}