<PRE><B>Question 806619</B>
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If the argument is negative, then you are simply going around the unit circle clockwise instead of counter clock wise.  If it was *[tex \LARGE \frac{71\pi}{6}]  you would go around the circle 11 times and then end up at 71 - 66 is 5, so *[tex \LARGE \frac{5\pi}{6}].  Now go backwards around the circle ll times and *[tex \LARGE \frac{5\pi}{6}] further in the negative (clockwise) direction and where do you end up?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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My calculator said it, I believe it, that settles it
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