Question 806273
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The *[tex \Large x]-intercept is a point with coordinates *[tex \Large (a,0)].  Substitute 0 in place of *[tex \Large y] in your equation and then solve for *[tex \Large x].  That *[tex \Large x]-value will be the *[tex \Large a] you need. 


The *[tex \Large y]-intercept is a point with coordinates *[tex \Large (0,b)].  Substitute 0 in place of *[tex \Large x] in your equation and then solve for *[tex \Large y].  That *[tex \Large y]-value will be the *[tex \Large b] you need.  


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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