Question 806238
x^2+6x+8/2x^2-4x-16 divided by 2x^2+12x+16/x+2
{{{((x^2+6x+8)/(2x^2-4x-16))/((2x^2+12x+16)/(x+2))}}}
This can be factored and simplified as:
{{{((x+4)(x+2)(x+2))/(2(x-4)(x+2)2(x+2)(x+4)) = 1/(4(x-4))}}}