Question 806148
let the numbers be x & y
xy=28

x=28/y

y-2x=1

subxtitute x

y-2(28/y)=1

y^2-56=y

y^2-y-56=0

y^2-8y+7y-56=0

y(y-8)+7(y-8)=0

(y-8)(y+7)=0

y=8 OR -7

xy = 28
x=-7
so y =-4

(-7,-4)

y=8
then x= 28/8
x=3.5

(3.5,8)