Question 806109
Twice the sum of a number and 3 times a second numbers is 4.  The difference of ten times the second number and five times the first is 90.  Find the numbers.

one number -----------x
second number---y

2(x+3y)=4
/2
x+3y=2
10y-5x=90

1    	x	+	3    	y	=	2    	.............1	
Total value								
-5    	x	+	10    	y	=	90    	.............2	
Eliminate	y							
multiply (1)by		-10    						
Multiply (2) by		3    						
-10    	x		-30    	y	=	-20    		
-15    	x	+	30    	y	=	270    		
Add the two equations								
-25    	x				=	250    		
/	-25    							
x	=	-10    						
plug value of			x	in (1)				
1    	x	+	3    	y	=	2    		
-10    		+	3    	y	=	2    		
			3    	y	=	2    	+	10    
			3    	y	=	12    		
				y	=	4    		
x=-10,y=4