<PRE><B>Question 805895</B>
The length of a rectangle is 5 times its width.
L = 5w
 When the length is decreased by 3m and the width is increased by 2m, the area of the new rectangle is 60m squared.
(L-3)*(w+2) = 60
Replace L with 5w
(5w-3)(w+2) = 60
FOIL
5w^2 + 10w - 3w - 6 = 60
5w^2 + 7w - 66 = 0
Factors to
(5w+22)(w-3) = 0
the positive solution
w = 3 m is the original width
and
5(3) = 15 m is the length
:
:
Check this 
(15-3)(3+2) = 
12*5 = 60



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