Question 805827
If the names are taken out one by one out of a hat containing all 30 names,
and are written in order on a list, there are
{{{30*29*28*27*26*25}}} possible lists.
With just the names of the 11 men, we can make only
{{{11*10*9*8*7*6}}} of those lists.
As a fraction of all the possible lists, that is
{{{11*10*9*8*7*6/(30*29*28*27*26*25)=22/28275}}}
It really does not matter how the names are randomly selected.
In only {{{22/28275}}} of the cases there would be only males selected.
The probability is
{{{22/28275}}}= approximately{{{0.0007781}}} or 0.07781%.
It can also be stated as the probability is {{{1:x}}} one in x.
{{{22/28275=1/x}}} --> {{{x=28275/22}}}= approximately{{{1285}}}
There is a 1 in 1285 probability of selecting only men.