Question 805686
I = initial pop
P = resulting pop in three weeks
{{{P=I*e^(kw)}}}, w is number of weeks.
{{{10=1*e^(k*3)}}} keeping the time unit as weeks.


{{{ln(10)=3k*ln(e)}}}
{{{ln(10)=3k}}}
{{{highlight(k=(1/3)ln(10))}}}


You wanted to call the population , N, so say
{{{N=500e^(kw)}}}, but you would still want to compute k before finishing the function.