Question 805721
Dividing the second equation by the first,
{{{128/32=a*b^3/(a*b^2)}}}
{{{4=b}}}
{{{highlight(b=4)}}}
Then, substituting that value for {{{b}}}
{{{32=a*4^2}}}
{{{32=16a}}}
{{{a=32/16}}}
{{{highlight(a=2)}}}