Question 805666
solve the equation for solutions over the interval [0,360)

      
     
        2 sin x -3 = -csc x
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2sin(x) - 3 = -1/sin(x)
{{{2sin^2(x) - 3sin(x) + 1 = 0}}}
(2sin - 1)*(sin - 1) = 0
sin = 1
x = 90 degs
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sin = 1/2
x = 30, 150 degs