Question 805655
{{{(-216)^(2/3)=((-6)^3)^(2/3)=(-6)^((3*(2/3)))=(-6)^2=highlight(36)}}}
{{{(1/16)^(1/4)}}}={{{(1/16)^0.25}}}={{{1^0.25/16^0.25}}}={{{1/(2^4)^0.25}}}={{{1/2^((4*0.25))}}}={{{1/2^1}}}={{{highlight(1/2)}}}
 
Note: I had to use {{{0.25}}} instead of {{{1/4}}} because the exponents display in a large font size that makes the displayed expression confusing,
and {{{1^(1/4)/16^(1/4)}}} was not as easy to interpret as {{{1^0.25/16^0.25}}}