Question 805610
Find all values of t in the interval [0, 2π] satisfying the given equation: 
6 sin 2t + 3 tan 2t = 0. And 6 is under a square root
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{{{sqrt(6)*sin(2t) + 3tan(2t) = 0}}}
Use x for 2t
{{{sqrt(6)*sin(x) + 3sin(x)/cos(x) = 0}}}
{{{sin(x)*(sqrt(6) + 3/cos(x)) = 0}}}
sin(x) = 0
x = 2t = 0, pi, 2pi
t = 0, pi/2, pi
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{{{sqrt(6) + 3/cos(x) = 0}}}
{{{sqrt(6)*cos(x) + 3 = 0}}}
{{{cos(x) = -3/sqrt(6)}}}
|cos(x)| > 1, no real number solution