Question 805614


 

Let {{{x}}} be the number of {{{nickels}}}. So {{{5x}}} is the amount of money in nickels.
Let {{{y }}}be the number of {{{dimes}}}. So {{{10y}}} is the amount of money in dimes.

  given:

{{{x+y=13}}}...................eq.1
{{{5x+10y=95}}}.........eq.2
______________________ solve the system

{{{x+y=13}}}...................eq.1.....solve for {{{x}}}
{{{x =13-y}}}...................eq.1a................substitute in eq.2

{{{5(13-y)+10y=95}}}.........eq.2.....solve for {{{y}}}

{{{65-5y+10y=95}}}

{{{5y=95-65}}}

{{{5y=30}}}

{{{y=30/5}}}

{{{highlight(y=6)}}}........the number of {{{dimes}}}


{{{x =13-y}}}

{{{x =13-6}}}

{{{highlight(x =7)}}}.............the number of {{{nickels}}}

so, you have  {{{6}}} dimes and {{{7}}} nickels