Question 805611
{{{y= 2x + 5}}}
{{{x^2 + y^2 + 6x - 2y + 2 = 0}}}
substitute 2x+5 for y 
{{{x^2 + (2x+5)^2 + 6x - 2*(2x+5) + 2 = 0}}}
(x+1)*(5 x+17) = 0
x = -17/5,   y = -9/5
x = -1,   y = 3