Question 805571
-(t - 3)^2 + 6(t - 3) - 11 
-(t^2+9-6t)+6t-18-11=0
-t^2-9+6t+6t-18-11=0
-t^2+12t-38=0
t^2-12t+38=0
D=b^2-4ac
D=(-12)^2-4x1x38
D=144-152
D=-8  roots will be imaginary

x=-(-12)+2sqrt2i/2   or x=-(-12)-2sqrt2i/2
x=12+2sqrt2i/2     or x=12-2sqrt2i/2
by takinh common 2 and cancelling we will get 
x=6+sqrt2i    or 6-sqrt2i
by adjusting negative sign
we will get roots of equations as 
x=-6-sqrt2i    or  x=-6+sqrt2i
Answer