Question 805566
2^x=1/2

{{{2^(x)= 2^(-1)}}}

x=-1




Q2.    By considering powers of 2, solve the following equation
          0.25^x=32^(3-x)

(1/4)^x= 32^(3-x)

(1/2^2)^x= 2^5(3-x)

2^-2x = 2^(5(3-x))

-2x=5(3-x)

-2x=15-5x

3x= 15
x=5