Question 68212
:
{{{ (625a^2b-125ab^2)/25a^2b^2)}}}
:
It's Ok to put the numerators over separate denominators like this:
{{{ (625a^2b)/(25a^2b^2)}}} - {{{ (125ab^2)/(25a^2b^2)}}}
;
Do some canceling and you will have:
{{{ (25)/(b)}}} - {{{ (5)/(a)}}}
:
The common denominator will ab:
{{{(25a - 5b)/(ab)}}}
:
You can factor out the 5
{{{(5(5a - b))/(ab)}}}