Question 805397
Find X if 2^x+1 = 8 root 2
{{{2^x + 1 = root(8,2)}}}
{{{2^x  = root(8,2) -1}}}
{{{x*log(2) = log(root(8,2) -1)}}}
{{{x = (log(root(8,2) -1))/log(2)}}}
Just calculator work from there.