Question 805287
let the terms be a,a+d,a+2d

a+a+d+a+2d= 27
3a+3d=27
/3
a+d=9

a(a+d)(a+2d)=504
a+d =9
a*9*(9+d)=504

a= 9-d
(9-d)(9+d)*9=504

(9+d)(9-d)=504/9
9^2-d^2=56
d^2=81-56
d^2=25

d=+/-5

a+d =9

when d = 5
a=4
the numbers are 4,9,15

The same when you take d=-5




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