Question 68215
Please help me simplify this equation: {{{ ((a-b)/(a+b))/((a^2-b^2)/(a^2+2ab+b^2))}}}

{{{a^2-b^2}}}={{{(a-b)(a+b)}}} and
{{{a^2+2ab+b2}}}={{{(a+b)^2}}}


Now lets put them back together and see what we have:

{{{((a-b)/(a+b))/((a-b)(a+b)/(a+b)^2)}}} multiply numerator and denominator by {{{(a+b)^2}}} and we have:



{{{(((((a+b)^2)(a-b))/(a+b))/(((a+b)^2)(a-b)(a+b)))/(a+b)^2)))}}} reduce fractions:



{{{((a-b)(a+b))/((a-b)(a+b))}}}=1


Hope this helps-----ptaylor