Question 805135
n=3; -6 and i are zeros; f(-3)= 60
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f(x) = a(x-i)(x+i)(x+6) = a(x^2+1)(x+6)
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a(x^3+6x^2+x+7)
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f(-3) = a[(-3)^3 + 6(-3)^2 + (-3) + 7] = 60
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a[-27+54+4] = 60
a[31] = 60
a = 60/31
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Equation:
f(x) = (60/31)(x^3+6x^2+x+7)
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Cheers,
Stan H.
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