Question 804783
start by making the equation equal to 0.
{{{75x^2=60x+12}}}
{{{75x^2-60x-12=0}}}
each of these coefficients can be divided by 3.
{{{3(25x^2-20x-4)=0}}}
you can't factor this number so you need to use the quadratic equation. We will ignore the 3 for now
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-(-20) +- sqrt( (-20)^2-4*25*(-4) ))/(2*25) }}}
{{{x = (20 +- 20 sqrt(2))/(50) }}}
simplify
{{{x = (2 +- 2sqrt(2))/(5)}}}
now we will bring the 3 back from earlier
{{{x=3((2 +- 2sqrt(2))/(5))}}}
{{{x=(6 +- 6sqrt(2))/(5)}}}