Question 68100
Divide a^3 b^4 c^6 by a^4 b^2, then divide that by a^2 b^3 d  The posted answer is c divided by a^3 b d.  How was that obtained.  Can you "spell" out the thinking and process that led to that answer?
When you divide like bases, you subtract their exponents.
{{{a^(3-4-2)*b^(4-3-2))c^6*d^(0-1)}}}
{{{a^(-3)b^(-1)c^6d^(-1)}}}  Anything with a negative exponent goes into the denominator:
{{{C^6/(a^3b^1d^1)}}}
{{{highlight(C^6/(a^3bd))}}}
Another way to do it is this:  
{{{a^3b^4c^6/(a^4b^2)}}} divided by {{{a^2b^3d}}}  Flip the last term over and multiply:
{{{(a^3b^4c^6/(a^4b^2))*(1/(a^2b^3d))}}}
{{{a^3b^4c^6/((a^4b^2)(a^2b^3d))}}}
{{{a^3b^4c^6/(a^(4+2)b^(2+3)d)}}}   add the exponents of like bases when multiplying.
{{{a^3b^4c^6/(a^6b^5d)}}}  subtract the smaller exponents of like bases and cancel.
{{{c^6/(a^(6-3)*b^(5-4)d)}}}
{{{highlight(c^6/(a^3bd))}}}
Hope that clears things up!
Happy Calculating!!!