Question 804723
Let x be the smaller and let y be the larger.

y = 4x + 2  <-- "The larger of the two numbers is 2 more than 4 times the smaller."

x+y = 67  <--- "The sum is 67"


We have a system of equations, and since we have one of these already solved (equation 1), then we are going to use substitution.

Therefore I will use y=4x+2  for my 2nd equation and get everything in terms of x.

x + (4x+2) = 67

5x + 2 = 67

5x = 65

x = 13

Since x = 13, then   13 + y = 67, so y = 54.

13, 54.