Question 804695
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You aren't explaining this very well, but I'm guessing you mean that you have one of those problems where they say 6 pencils and 2 tablets cost some amount, and then 4 pencils and 3 tablets cost some other amount, then they want you to figure out the cost of one pencil and the cost of one tablet.


Let *[tex \Large x] represent the cost of one of the items, *[tex \Large y] represent the cost of the other item, *[tex \Large n_1] and *[tex \Large n_2] bet the two different numbers of item 1, and *[tex \Large m_1] and *[tex \Large m_2] be the two different numbers of item 2, and finally, let *[tex \Large C_1] be the cost of the first combination and *[tex \Large C_2] be the cost of the second combination.  Then you can form two linear equations in two variables:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n_1x\ +\ m_1y\ =\ C_1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n_2x\ +\ m_2y\ =\ C_2]


Using your given numbers, solve the 2X2 system for *[tex \Large x] and *[tex \Large y]


Oh, and if you would be so very kind, spell out "you" in the future. Save the cutesy teen-age text-speak for your friends and treat people trying to help you with a little more respect.  Thank you. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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