Question 804563
{{{x^2-2x-5=0}}}

{{{x^2-2x+1 -1-5=0}}


{{{(x-1)^2=5+1}}}


{{{(x-1)^2=6}}}

take the square root

x-1= +/-{{{sqrt(6)}}}

x= 1+/-{{{sqrt(6)}}}