Question 804544
find slope
{{{(6-9)/(3-(-4))=3/7}}}
a line perpendicular to that would have a slope of {{{-7/3}}}
{{{y=(-7/3)x+b}}}
plug the point into the equation
{{{-7=(-7/3)5+b}}}
{{{-7=-11(2/3)+b}}}
{{{4.66=b}}}
the final equation is
{{{y=(-7/3)x+4.66}}}