Question 804512
{{{x(4x+18)=10}}}
get equation equal to 0
{{{4x^2+18x=10}}}
{{{4x^2+18x-10=0}}}
use quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-18 +- sqrt( 18^2-4*4*(-10) ))/(2*4) }}}
{{{x=(-18+-sqrt(484))/(8)}}}
{{{x=(-18+-22)/8}}}
{{{x=(-18+22)/8}}}
{{{x=1/2}}}
{{{x=(-18-22)/8}}}
{{{x=-5}}}
the values of x are {{{1/2}}} and {{{-5}}}