Question 804461
The area of a rectangle is 36 square inches. The perimeter of the rectangle is 36 inches. What are the dimensions of the rectangle to the nearest hundredth of an inch? 
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Area:: L*W = 36
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Perimeter:: 2(L+W) = 36
L + W = 18
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Substitute for "L" and solve for "W"::
(18-W)W = 36
-W^2 + 18W = 36
W^2 - 18W + 36 = 0
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W = [18 +-sqrt(18^2-4*1*36)]/(2)
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W = [18+-sqrt(180)]/(2)
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W = (18+6sqrt(5))]/(2)
W = 15.71 inches
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Solve for "L"::
L + W = 18
L + 15.71 = 18
L = 2.29 inches
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Cheers,
Stan H.
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