Question 804177
Suppose that the endpoints of the shorter leg of a 30°-60°-90° triangle are (4, –2) and (7, 2). What is the length of the longer leg?
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Label the point A(4,-2) and B(7,2)  (don't put a space after the comma)
AB = sqrt(diffy^2 + diffx^2) = sqrt(4^2 + 3^2) = 5
The hypotense length is 2*AB = 10
The longer leg is {{{sqrt(10^2 - 5^2) = 5*sqrt(3)}}}