Question 804058
{{{4/(5(d-2))=(-3(d+3))/4}}}
{{{4/(5d-10)=(-3d-9)/4}}}
You can cross multiply
{{{16=(5d-10)(-3d-9)}}}
{{{16=-15d^2-15d+90}}}
{{{0=-15d^2-15d+74}}}
use quadratic formula
{{{d = (-(-15) +- sqrt( (-15)^2-4*(-15)*74 ))/(2*(-15)) }}}
{{{d=(15+-sqrt(4665))/-30}}}