Question 803791

{{{log (4,x)=9/2 }}}.........in base {{{10}}} will be


{{{log (x)/log(4)=9/2 }}}.........cross multiply

{{{2log (x)=9log(4) }}}

{{{log (x^2)=log(4^9) }}} =>

{{{x^2= 4^9 }}}......=> {{{4^9=512^2}}} 

{{{x^2= 512^2 }}}

{{{x=  512 }}}